evildragon
Veteran Member
Lately I've been learning about CPU's and addressable memory, and something doesn't add up, on the PC side of things.
8086. It's a 16-bit CPU, and uses 16-bits to access RAM. But, how? From my math, it shouldn't be possible.
2 to the 16th power is 64KB RAM. So how is it accessed then? Bank switching?
8086. It's a 16-bit CPU, and uses 16-bits to access RAM. But, how? From my math, it shouldn't be possible.
2 to the 16th power is 64KB RAM. So how is it accessed then? Bank switching?