Looking at your inventory, the best I come up with is to make a high power load for the 5v out of the four 0.1Ω resistors. That will be to put two 0.1Ω in series making a 0.2Ω load that will draw 25A@5V. Do the same thing with the other two 0.1Ω, for a total load of 50A@5V (250W).
To mount the resistors, I'd make up a paddle board (1/4 ply?) with machine screws through it (countersink, maybe 2 inches long?). Put nuts on the screws all the way down to the board, turning them into studs (3 in a row) at the hole spacing of the resistors. Another set of nuts to act as stand-offs. maybe 1/2 inch from the end of the screws. Mount the two resistors onto the studs. (two resistors share the center screw) Apply a final nut to the center screw.
For load wire, get some #12 or heavier stranded insulated wire. It would be nice to have multiple colors, but if not come up with a tagging method. Cut wire sections into convenient lengths and crimp lugs on the ends. You'll need to size one end to be mounted where you've been attaching your loads previously. The others will go to the remaining ends of the mounted resistor pair.
Repeat that entire thing a second time. You might do something clever like use both sides of the same paddle and place it in front of a cooling fan.
Hopefully, that all makes sense. (I almost lost that post to an expired token. Got it back via auto-save)
That 4 resistor array will keep each resistor well under it's power rating, and get your supply over 40%. Maybe the other resistors can play a part later on, loading other power supply sections. Should more resistors become available later, they can be added in the same manner.
Speaking of other sections - since the 15V supply seems to be the source for the reference voltage, it would be a good idea to measure it whenever the DC ON light indicates a problem. You might even do that once with the real system boards again if the opportunity presents itself.
Is this thinking clear for you? (3-4am isn't my best time)